(x^2+3x)(x^2+3x+4)=-4

(X-1)(X-2)=X*X-3X+2X*X-3X+2=(X-1)(X-3)X*X+4X+4=X(X-4)+4X*X+Y*Y=(X+Y)(X-Y)哪一个因式分解是正确的(X-1)(X-2)=X*X-3X+2X*X-3X+2=(X-1)(X-

已知X=4-根号3求(X*X*X*X-6X*X*X-2X*X+18X+23)/(X*X-8X+15)的值紧急,,明天有用,,已知X=4-根号3求(X*X*X*X-6X*X*X-2X*X+18X+23)/(X*X-8X+15)的值紧急,,明天

(x-3/x-2)-(x-2/x-1)=(x-5/x4)-(x-4/x-3)(x-3/x-2)-(x-2/x-1)=(x-5/x4)-(x-4/x-3)(x-3/x-2)-(x-2/x-1)=(x-5/x4)-(x-4/x-3)

x-2x+3x-4x+5x.+99x-100x=25求解x-2x+3x-4x+5x.+99x-100x=25求解x-2x+3x-4x+5x.+99x-100x=25求解x(1-2+3-4+...+99-100)=25x[(1-2)+(3-4

2x+3x+4x+5x+x+6x+7x=1002x+3x+4x+5x+x+6x+7x=1002x+3x+4x+5x+x+6x+7x=1002x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/727x=100

x(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=27求xx(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=27求xx(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=27求xx²＋x＋x＋2＋x

X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X

x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7x=?x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7x=?x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7x=?x+2/x+1-x+4/x+3=x+

x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002x^4+x^3+x^2+x+1=

x^2-3x=x-4x^2-3x=x-4x^2-3x=x-43）x^2-4x+4=0(x-2)^2=0x=24)(x-7)(x+6)=0x=7,-65)(x-3)^2-15=0(x-3)^2=15x=3±√156)(2x-1)(x+1)=0

4x-2(x-3)=x4x-2(x-3)=x4x-2(x-3)=x解如下：4x-2x+6=x2x-x=-6x=-6—————————————————————————————有问题欢迎向我的团队【定向求助】哦我们将在第一时间内尽力为您解答\(

x(x-4)=-3x^2x(x-4)=-3x^2x(x-4)=-3x^2x(x-4)=-3x²-4x+3=0(x-1)(x-3)=0x=1,x=3x²反比例函数则x的次数是-1且系数不等于0k²-6k+4=-1

x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?x+2x

[(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/(x+4)]/[(x的平方+7x+13)/(x的平方+8x+15)][(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/

x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4(x+2)/(x+1)-(x+3)/(x+2)-(x+

(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)(x+

x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)前面多项式提取公因式x就有前面两个式子合并为：x

已知关于x的二次多项式：a(X*X*X-X*X+3X)+b(2X*X+X)+X*X*X-5当X=2时值为－17,求当X=-2时该多项式的值.已知关于x的二次多项式：a(X*X*X-X*X+3X)+b(2X*X+X)+X*X*X-5当X=2时

x^5-x^4+x^3-x^2+x-1x^5-x^4+x^3-x^2+x-1x^5-x^4+x^3-x^2+x-1x^5-x^4+x^3-x^2+x-1　　=x^4(x-1)+x^2(x-1)+(x-1)　　=(x-1)(x^4+x^2+1

(X+1)X(X+2)X(X+3)=504(X+1)X(X+2)X(X+3)=504(X+1)X(X+2)X(X+3)=504等价于x^3+6x^2+11x-498=0令左边等于y试根x=6时y=0做整式除法y/(x-6)=x^2+12x+