计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51).因为1/(1*2)=1-(1/2),1/(2*3)=(1/2)*(1/3),1/(3*4)=(1/3)-(1/4),……,1/(9*10)=(1/9)-(1/10).所以1/(1*2)+1/(2*3)+1/(3*4)+…+1/(9

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 01:06:43
计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51).因为1/(1*2)=1-(1/2),1/(2*3)=(1/2)*(1/3),1/(3*4)=(1/3)-(1/4),……,1/(9*10)=(1/9)-(1/10).所以1/(1*2)+1/(2*3)+1/(3*4)+…+1/(9

计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51).因为1/(1*2)=1-(1/2),1/(2*3)=(1/2)*(1/3),1/(3*4)=(1/3)-(1/4),……,1/(9*10)=(1/9)-(1/10).所以1/(1*2)+1/(2*3)+1/(3*4)+…+1/(9
计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51).
因为1/(1*2)=1-(1/2),1/(2*3)=(1/2)*(1/3),1/(3*4)=(1/3)-(1/4),……,1/(9*10)=(1/9)-(1/10).所以1/(1*2)+1/(2*3)+1/(3*4)+…+1/(9*10)=1-(1/2)+(1/2)-(1/3)+(1/3)-(1/4)+…+(1/9)-(1/10).
是计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51)。

计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51).因为1/(1*2)=1-(1/2),1/(2*3)=(1/2)*(1/3),1/(3*4)=(1/3)-(1/4),……,1/(9*10)=(1/9)-(1/10).所以1/(1*2)+1/(2*3)+1/(3*4)+…+1/(9
25/51
因为1/(1*3)=(1/1-1/3)/2,1/(3*5)=(1/3-1/5)/2,1(5*7)=(1/5-1/7)/2...1(49*51)=(1/49-1/51)/2
所以1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51)=(1-1/3+1/3-1/5+1/5...+1/49-1/51)
=(1-1/51)/2=25/51
楼上2个答案不对