(2x)^20×(x-1)^40/(3x+1)^60+1的极限Limx→ 无穷

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(2x)^20×(x-1)^40/(3x+1)^60+1的极限Limx→ 无穷

(2x)^20×(x-1)^40/(3x+1)^60+1的极限Limx→ 无穷
(2x)^20×(x-1)^40/(3x+1)^60+1的极限Limx→ 无穷

(2x)^20×(x-1)^40/(3x+1)^60+1的极限Limx→ 无穷
Limx→ 无穷((2x)^20×(x-1)^40/(3x+1)^60+1)
=Limx→ 无穷(2^20*x60/(3x)^60)
=2^20/3^60
忽略低次项,只考虑高次项

x{x+1}{x-1}}x-2}{x-3}-40 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. x{x+1}{x-2}{x-3}-40 分解因式:x(x-1)(x+2)(x+3)-40 因式分解(x+1)(x-2)(x-3)(x-6)+20 计算:1/x(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-19)(x-20) 2x(x-1)-x(3x+2)=(-x-1)(x+6)-20 解方程X(X+1)-X(X-3)=2(X+1)(X-1)+20 x(x+1)²-x(x²-3)-2(x+1)(x-1)=20 x+3/20x=46 ,x-1/5x=40 ,x-1/2x=3/4 ,x-0.2x=18解方程 x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X |x+1|-|x|+|x-2|-|-x+3|已知x+2 x^5-x^4+x^3-x^2+x-1 (X+1)X(X+2)X(X+3)=504 x-2=(104-x)+2 6x-59=10x-75 (x+10)+(x-15)=280-x4(x-62)=x-38 60x-40=(60+20)*(x-5) 32x+32*0.5-25x+64x=24x+496-49x x+15=3*(109-x ) 5(3x-1.4)=2(6x-0.5) 3(x+0.9)=5(x-1.7) 13x-4(2x+5)=17(x-2)-4(2x-1) (13x+8)/3=5x-1x-60=2[(3561-x)+100]+1 (x+9)+12=2[(x-9)-1