已知函数f(x)=2asin(2x-π/6)+b的定义域为[0,π/2],值域为[-5,1],求常数a,b的值x∈[0,π/2]则 2x-π/6 ∈[-π/6,5π/6]所以 sin(x-π/6) ∈[-1/2,1](1) a>0最大值为2a+b=1最小值为-a+b=-5所以 a=2,b=-3(2)a

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