已知1/x-1/y=3,则代数式(2x-14xy-2y)/(x-2xy-y)的值为多少?

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已知1/x-1/y=3,则代数式(2x-14xy-2y)/(x-2xy-y)的值为多少?

已知1/x-1/y=3,则代数式(2x-14xy-2y)/(x-2xy-y)的值为多少?
已知1/x-1/y=3,则代数式(2x-14xy-2y)/(x-2xy-y)的值为多少?

已知1/x-1/y=3,则代数式(2x-14xy-2y)/(x-2xy-y)的值为多少?
1/x-1/y=3
(y-x)/xy=3
y-x=3xy
(2x-14xy-2y)/(x-2xy-y)
=[2(x-y)-14xy]/(x-y-2xy)
=(-6xy-14xy)/(-3xy-2xy)
=(-20xy)/(-5xy)
=4

(1) y=60/x
(2) w=y*(x-2)=60(x-2)/x=60-120/x (2≤x≤10)
根据反比例函数的单调性,当x=10时,w取到最大,为48

1/x-1/y=3
(y-x)/xy=3
y-x=3xy
原式=[2(x-y)-14xy]/(x-y-2xy)
=(-6xy-14xy)/(-3xy-2xy)
=(-20xy)/(-5xy)
=4

前面一个问题答案是4
(2x-14xy-2y)/(x-2xy-y)
=(2/y-14-2/x)/(1/y-2-1/x) (即分子分母同除以xy)
=(-20)/(-5) (即代入1/x-1/y=3)
=4
追问的那个问题呢,
(1) y=60/x
(2) w=y*(x-2)=60(x-2)/x=60-120/x (2≤x≤10)

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前面一个问题答案是4
(2x-14xy-2y)/(x-2xy-y)
=(2/y-14-2/x)/(1/y-2-1/x) (即分子分母同除以xy)
=(-20)/(-5) (即代入1/x-1/y=3)
=4
追问的那个问题呢,
(1) y=60/x
(2) w=y*(x-2)=60(x-2)/x=60-120/x (2≤x≤10)
根据反比例函数的单调性,当x=10时,w取到最大,为48

收起

(2x-14xy-2y)/(x-2xy-y)
=(2/y-14-2/x)/(1/y-2-1/x) (即分子分母同除以xy)
=(-20)/(-5)
=4