double f(double x); {double a=0;int i; for (i=0;i

来源：学生作业帮助网编辑：作业帮时间：2024/04/28 06:11:52

double f(double x); {double a=0;int i; for (i=0;i
double f(double x); {double a=0;int i; for (i=0;i

double f(double x); {double a=0;int i; for (i=0;i
函数f(x)返回x^2 + 1
循环体内 a +=f((double)i) 等价于 a = a + f((double)i) a的初始值为0,所以循环体内的语句是累加f(i).
从for(i = 0; i < 30; i += 10)看出,i的初始值为0,每次递增10,三次递增后达到30,不满足i

有句C语言看不懂double f (double a, double b, double c,double d, double x) double fun(int i,double x,double double double double double double double double double Double double double double double double double double