(1)2x+1/x-3+2x-1/3x-2=0 (2)x/x²-7x+12=0上面写错了 第二题x/x²-7x+12=1

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(1)2x+1/x-3+2x-1/3x-2=0 (2)x/x²-7x+12=0上面写错了 第二题x/x²-7x+12=1

(1)2x+1/x-3+2x-1/3x-2=0 (2)x/x²-7x+12=0上面写错了 第二题x/x²-7x+12=1
(1)2x+1/x-3+2x-1/3x-2=0
(2)x/x²-7x+12=0
上面写错了 第二题x/x²-7x+12=1

(1)2x+1/x-3+2x-1/3x-2=0 (2)x/x²-7x+12=0上面写错了 第二题x/x²-7x+12=1
没加括号,题意的歧意.
(1)(2x+1)/(x-3)+(2x-1)/(3x-2)=0
去分母得:(2X+1)(3X-2)+(2X-1)(X-3)=0,
去括号合并得:8X^2-8X+1=0
X=(8±4√2)/16=(2±√2)/4
经检验分母不为0,所以两个都是原方程的解.
(2)x/(x²-7x+12)=1
去分母得:X^2-8X+12=0,
(X-2)(X-6)=0
X1=2,X2=6
经检验:X1=2、X2=6都是原方程的解.

话说你这题目能写写清楚吗??
这题目是(2x+1/x-3)+(2x-1/3x-2)=0 呢?
还是2x+(1/x-3)+2x-(1/3x-2)=0呢????

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