(1+根号3)(1+根号2)(1-根号3)(1-根号2)

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(1+根号3)(1+根号2)(1-根号3)(1-根号2)

(1+根号3)(1+根号2)(1-根号3)(1-根号2)
(1+根号3)(1+根号2)(1-根号3)(1-根号2)

(1+根号3)(1+根号2)(1-根号3)(1-根号2)
(1+根号3)(1+根号2)(1-根号3)(1-根号2) =[(1+根号3)(1-根号3)(1-根号2)][(1+根号2)(1-根号2)] =(1-3)x(1-2) =-2x(-1) =2 答题不容易,如有不懂,今后不再回答!