6y^2+9y+2
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6y^2+9y+2
6y^2+9y+2
6y^2+9y+2
(y+(9-√33)/12)(y+(9+√33)/12)
这个无法用十字相乘法,所以只能先算出y的根,Y=+-根号下(11/48)-3/4
所以(Y+3/4-√(11/48)(y+3/4+√(11/48)
6y^2+9y+2
= 6 ( y^2 + 3y/2 + 9/16 ) -11/8
= 6 ( y + 3/4 ) ^2 - 11/8
= ( √ 6( y + 3/4 ) - √11/8 ) ( √ 6( y + 3/4 ) +√11/8 )
6Y^2+9Y+2
∵a=6,b=9,c=2 b^2-4ac=81-48=33
根=(-9±√33)/(2*6)
=-3/4±√33/12
6Y^2+9Y+2=6*(Y+3/4+√33/12)(Y+3/4-√33/12)
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