反导数不定积分..f'(x)=-14/(1-x^2)^(1/2)求f(x)f'(x)=11/(x^2+1)求f(x)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 11:54:12
反导数不定积分..f'(x)=-14/(1-x^2)^(1/2)求f(x)f'(x)=11/(x^2+1)求f(x)

反导数不定积分..f'(x)=-14/(1-x^2)^(1/2)求f(x)f'(x)=11/(x^2+1)求f(x)
反导数不定积分..
f'(x)=-14/(1-x^2)^(1/2)
求f(x)
f'(x)=11/(x^2+1)
求f(x)

反导数不定积分..f'(x)=-14/(1-x^2)^(1/2)求f(x)f'(x)=11/(x^2+1)求f(x)
f'(x)=-14/(1-x^2)^(1/2)
f(x)=∫-14/(1-x^2)^(1/2)dx=-14arcsinx+C
f'(x)=11/(x^2+1)
f(x)=∫11/(x^2+1)dx=11arctanx+C