acm wrong answer是由什么引起的?北邮一道简单的减法题：北邮一道简单的减法题：DescriptionCalculate A-BInputTwo integer a and b(-10^100 < a,b < 10^100)OutputOutput a-bSample Input1 2Sample Output-1#include using namespace std

为啥是wrong answer 为啥是wrong answer acm wrong answer是由什么引起的?北邮一道简单的减法题：北邮一道简单的减法题：DescriptionCalculate A-BInputTwo integer a and b(-10^100 < a,b < 10^100)OutputOutput a-bSample Input1 2Sample Output-1#include using namespace std 杭电acm 1008 题我的为什么是wrong answer acm简单的问题一直wrong answer有一些三个整数构成的整数群,它的结构是：第一行整数N表示后面有N个几个整数群,每个整数群由三个整数组成.尝试用＋、－、×、/(整除)来凑前两个数的计算结果 杭电acm 1159,公共子序列问题,我的思路漏掉什么了啊?老是wrong answer网上有人说是动态规划,我怎么没看出来呢……（新手,对该算法还不太懂）我的思路是这样的：读入两个字符串A、B对A的每一 杭电ACM problem 1002 A + B Problem II为什么会WRONG ANSWER?计算结果没错啊?#include acm中wrong answer at test 1与at test 4或者at test 10有区别吗? acm题为什么wrong answer啊John von Neumann, b. Dec. 28, 1903, d. Feb. 8, 1957, was a Hungarian-American mathematician who made important contributions to the foundations of mathematics, logic, quantum physics, meteorology, science, computers, and acm题目的a+b用c语言怎么写我写的是#includeint main(){int a,b;while(scanf(%d %d,&a,&b)==2){printf(%d ,a+b);}return 0;}他说wrong answer 杭电acm 2034wrong answer Problem Description参加过上个月月赛的同学一定还记得其中的一个最简单的题目,就是{A}+{B},那个题目求的是两个集合的并集,今天我们这个A-B求的是两个集合的差,就是做集合 acm的一道题贪心的酒鬼我总是wrong answer有没有人能挑战下,代码很短．c语言老李是个酒鬼.可惜他又是一个好吃懒做的人.他身上只有M 元钱,他知道商店啤酒的价格是 K 元钱每瓶,而且 N 个啤酒 关于画矩形的acm这道题哪里错了啊?系统老是说wrong answer这是问题：Description 给定一个矩形的宽和高,请画出该矩形.参见输出样例.Input 输入包含多组数据.每组数据一行,包含2个整数n 和m (0 < n, 很明显,你的答案是错的------------ -----------that your answer is wrong很明显,你的答案是错的------------ -----------that your answer is wrong Your answer to this question is c_______ ,but mine is wrong填什么? You entered wrong answer to bot protection question什么意思啊 简单acm题,为什么会wrong answer?DescriptionYour task is to Calculate a + b.InputThere are multiple test cases.Each test case contains only one line.Each line consists of a pair of real number a and b（0 新手,想做Acm题,在1002就卡了,这是为什么?反馈是：Wrong Answer at Test 1#includeusing namespace std;int main(){ const int M = 100;int i=0,max=0,min = 0,N;int A[M];cin>>N;while(i = N){cin>>A[i];++i;}max=A[0];min=A[0];for(i= 0;i!=N;++i){