a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)=?

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/27 13:40:27
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)=?

a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)=?
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)=?

a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)=?
2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)
=[(a-b)+(a-c)]/(a-b)(a-c)+[(b-c)+(b-a)]/(b-c)(b-a)+[(c-a)+(c-b)]/(c-a)(c-b)
=1/(a-c)+1/(a-b)+1/(b-a)+1/(b-c)+1/(c-b)+1/(c-a)
=[1/(a-c)+1/(c-a)]+[1/(a-b)+1/(b-a)]+[1/(b-c)+1/(b-c)]
=0+0+0
=0