求(log2^3+log8^9)(log3^4+log9^8+log3^2)的值
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求(log2^3+log8^9)(log3^4+log9^8+log3^2)的值
求(log2^3+log8^9)(log3^4+log9^8+log3^2)的值
求(log2^3+log8^9)(log3^4+log9^8+log3^2)的值
=(log2 3+log8 9)(log3 4+log9 8+log3 2)
=[log2 3+(2/3)log2 3][2log3 2+(3/2)log3 2+log3 2]
=(5/3)log2 3*(9/2)log3 2
=(15/2)(lg 3/lg 2)(lg 2/lg 3)
=15/2
求(log2^3+log8^9)
log8(9)*log2(3)
(log8 9/log2 3)=?
log8(9)/log2(3) 都忘记了说详细过程log底可以怎么算
log8^9/log2^3的值是
求(log2^3+log8^9)(log3^4+log9^8+log3^2)的值
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已知log2^3=a.则log8^3= log8^9=
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log8的9次方/log2的3次方=
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