int x='d'; printf("%c\n",'A'+(x-'a'+1)int x='d';printf("%c\n",'A'+(x-'a'+1)

int x=20;printf(“%d”,0 int x=20;printf(“%d”,0 int x=20; printf(%d ,x);呵呵 int *p1;int x=971; p1=&x,printf(%d,*(p1++)); void main() {int x=4;if(x++>=5)printf(%d/n,x);else printf(%d/n,x--); int x=6; x += x -= x * x; printf(x = %d ,x); int x=3,y=4; printf(%d,%d,(x.y),(y,x)); int x='d'; printf(%c ,'A'+(x-'a'+1)int x='d';printf(%c ,'A'+(x-'a'+1) int x = 3; do { printf(%3d,x -= 2 ); } while ( ( --x) ); ( ( --x) int x,y; x=13; y=5; {printf(%d,x%=(y/=2)); main( ) {int x=3; do {printf(%d ,x-=2;} while (--x)); } #includemain(){int x=3;do{printf(%d ,x-=2);}while(!(--x));} #includemain(){int x=3;do{printf(%3d ,x-=2);}while(!(--x));} int x=23;do {printf (%d,x--);}while(!x);有没有详细一点的解释? # include void main( ) { int x = 4 ; do { printf( %d ,x-- ) ; } while( x ) ; } main() {int x=10,i=1,j=2； printf (“%d,%o,%x ”,x,x,x)； printf (“i=%d ”,++i)； printf (“%c 输出结果是什么?main(){int x=10,i=1,j=2；printf (“%d,%o,%x ”,x,x,x)；printf (“i=%d ”,++i)；printf (“%c ”,i= =j ?’E’ 谁来帮我找找错啊int max(int a,int b);void main(){int x,y,z;int max(int a,int b);printf(input two numbers: );scanf(%d%d,&x,&y);z=max(x,y);printf(maxmum=%d,z);}int max(int a,int b);{if(a>b) return a;else return b;}------------------Con int i=9999;printf(%d ,printf(%d,printf(%d,printf(%d,i))));的结果解释