先化简,再求值:{(xy-2)^2+4xy-4}/(-xy),其中x=1.,y=-1/25

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 22:49:50
先化简,再求值:{(xy-2)^2+4xy-4}/(-xy),其中x=1.,y=-1/25

先化简,再求值:{(xy-2)^2+4xy-4}/(-xy),其中x=1.,y=-1/25
先化简,再求值:{(xy-2)^2+4xy-4}/(-xy),其中x=1.,y=-1/25

先化简,再求值:{(xy-2)^2+4xy-4}/(-xy),其中x=1.,y=-1/25
{(xy-2)^2+4xy-4}/(-xy)
={(xy-2)^2+2(xy-2)+1+2xy-1}/(-xy)
={[(xy-2)+1]^2+2xy-1}/(-xy)
={(xy-1)^2+2xy-1}/(-xy)
={(xy)^2-2xy+1+2xy-1}/(-xy)
=(xy)^2/(-xy)
=-xy
=-1*(-1/25)
=1/25

[(xy-2)²+4xy-4]/(-xy)
=(x²y²-4xy+4+4xy-4]/(-xy)
=-xy
=-1×(-1/25)
=1/25
望采纳