tanx=2,求2/3SIN^2X+1/4cox^2X的值
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tanx=2,求2/3SIN^2X+1/4cox^2X的值
tanx=2,求2/3SIN^2X+1/4cox^2X的值
tanx=2,求2/3SIN^2X+1/4cox^2X的值
2/3sin²x+1/4cos²x
=2/3(sin²x+cos²x)/sin²x+1/4*(sin²x+cos²x)/cos²x
=2/3(1+1/4)+1/4*(4+1)
=5/6+5/4
=25/12
解析:∵tanx=2
∴sinx=2√5/5,cosx=√5/5, 2/3sin²x+1/4cos²x=2/3*4/5+1/4*1/5=7/12
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