作业帮tan(π/6 -θ )+tan(π/6+θ)+根号3tan(π/6-θ)tan(π/6+θ)化简这个式子,tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+根号3tan(π/6-θ)tan(π/6+θ)tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+这个是怎么来的tan[(π/6-θ)+(
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![tan(π/6 -θ )+tan(π/6+θ)+根号3tan(π/6-θ)tan(π/6+θ)化简这个式子,tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+根号3tan(π/6-θ)tan(π/6+θ)tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+这个是怎么来的tan[(π/6-θ)+(](/uploads/image/z/3913196-68-6.jpg?t=tan%28%CF%80%2F6+-%CE%B8+%29%2Btan%28%CF%80%2F6%2B%CE%B8%29%2B%E6%A0%B9%E5%8F%B73tan%28%CF%80%2F6-%CE%B8%29tan%28%CF%80%2F6%2B%CE%B8%29%E5%8C%96%E7%AE%80%E8%BF%99%E4%B8%AA%E5%BC%8F%E5%AD%90%2Ctan%5B%28%CF%80%2F6-%CE%B8%29%2B%28%CF%80%2F6%2B%CE%B8%29%5D%2A%5B1-tan%28%CF%80-%CE%B8%29tan%28%CF%80%2F6%2B%CE%B8%29%5D%2B%E6%A0%B9%E5%8F%B73tan%28%CF%80%2F6-%CE%B8%29tan%28%CF%80%2F6%2B%CE%B8%29tan%5B%28%CF%80%2F6-%CE%B8%29%2B%28%CF%80%2F6%2B%CE%B8%29%5D%2A%5B1-tan%28%CF%80-%CE%B8%29tan%28%CF%80%2F6%2B%CE%B8%29%5D%2B%E8%BF%99%E4%B8%AA%E6%98%AF%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84tan%5B%28%CF%80%2F6-%CE%B8%29%2B%28)
tan(π/6 -θ )+tan(π/6+θ)+根号3tan(π/6-θ)tan(π/6+θ)化简这个式子,tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+根号3tan(π/6-θ)tan(π/6+θ)tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+这个是怎么来的tan[(π/6-θ)+(
tan(π/6 -θ )+tan(π/6+θ)+根号3tan(π/6-θ)tan(π/6+θ)化简这个式子,
tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+根号3tan(π/6-θ)tan(π/6+θ)
tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+这个是怎么来的
tan[(π/6-θ)+(π/6+θ)]*[1-tan(π/6-θ)tan(π/6+θ)]+写错了
tan(π/6 -θ )+tan(π/6+θ)+根号3tan(π/6-θ)tan(π/6+θ)化简这个式子,tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+根号3tan(π/6-θ)tan(π/6+θ)tan[(π/6-θ)+(π/6+θ)]*[1-tan(π-θ)tan(π/6+θ)]+这个是怎么来的tan[(π/6-θ)+(
是由tan(α+β)=(tanα+tanβ)/(1-tanαtanβ)得出的
原式求tan(π/6 -θ )+tan(π/6+θ)+√3tan(π/6-θ)tan(π/6+θ)
先看前一部分
由 tan(A+B) = (tanA+tanB)/(1-tanAtanB)
tan(π/6 -θ )+tan(π/6+θ)=tan(π/3)（1-tan(π/6-θ)tan(π/6+θ)）
tan(π/3)=√3
提出一个公因式√3
全式=√3（1-tan(π/6-θ)tan(π/6+θ)+tan(π/6-θ)tan(π/6+θ)）
=√3