若数列{an}满足:a(n+1)=1—1/an且a1=2,则a2011等于

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 20:57:18
若数列{an}满足:a(n+1)=1—1/an且a1=2,则a2011等于

若数列{an}满足:a(n+1)=1—1/an且a1=2,则a2011等于
若数列{an}满足:a(n+1)=1—1/an且a1=2,则a2011等于

若数列{an}满足:a(n+1)=1—1/an且a1=2,则a2011等于
a(n+3)=1-1/a(n+2)=1-a(n+1)/(a(n+1)-1)=-1/(a(n+1)-1)=an,因此{an}以3为周期,故a2011=a(670*3+1)=a1=2;

代几个进去会发现这个数列是有周期的
a1=2,a2=1/2 , a3= -1 , a4 =2=a1 ,a5=a2,...
a2011=a1=2

数列[An]满足a1=2,a(n+1)=3an-2 求an 若数列{an}满足:a(n+1)=1—1/an且a1=2,则a2011等于 若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a(n+1)=2^n·an,则数列an的通项公式? 已知数列{an}满足a1=33,a(n+1)-an=2n,求an/n的最小值 已知数列an满足a1=2,an=a(n-1)+2n,(n≥2),求an 已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=? 已知数列{a}满足a1=1/2,a(n+1)=an+1/(n^2+n),求an已知数列{a}满足a1=1/2,a(n+1)=an+1/(n^2+n),求an 周期性数列问题i已知数列{an}满足a(n+1)=2an (0 已知数列{an}满足a1=1,a(n+1)=2an+1(n∈N)(1)求数列{an}的通项公式(2)若数列{bn}满足4^(b1-1).4^(b2-1)已知数列{an}满足a1=1,a(n+1)=2an+1(n∈N*)(1)求数列{an}的通项公式(2)若数列{bn}满足4^(b1-1).4^(b2-1).4^(b3- 数列﹛an﹜满足an=2a(n+1)-1,怎么证明等差? 数列{an},定义数列满足:Δan=a(n+1)-an,定义数列{(Δan)的平方}满足:(Δan)的平方=Δa(n+1)-Δan,若数列{2^Δan}中各项均为1,且a21=a2012=0,则a1=?若数列{(Δan)的平方}中各项均为1 不好意思, 已知数列{An}满足a1=1,a(n+1)=2an+1 求证数列{an+1}是等比数列 求数列{an}通式 在数列an中,a1=1,且满足a(n+1)=3an +2n,求an 若数列{an}满足a1>0,且a(n+1)=(n/n+1)乘以an,则数列{an}是 递增数列,递减数列 常数列 摆动数列求详解 已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an= 数列证明题一题设数列{An}满足:A1=1,且当n∈N*时,An^3+An^2×[1-A(n+1)]+1=A(n+1)求证:数列{An}是递增数列.