作业帮x^3+y^3+z^3-3xyz变成(x+y+z)(x^2+y^2+z^2-xy-yz-xz)步骤
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 11:19:14
x^3+y^3+z^3-3xyz变成(x+y+z)(x^2+y^2+z^2-xy-yz-xz)步骤
x^3+y^3+z^3-3xyz变成(x+y+z)(x^2+y^2+z^2-xy-yz-xz)步骤
x^3+y^3+z^3-3xyz变成(x+y+z)(x^2+y^2+z^2-xy-yz-xz)步骤
x^3+y^3+z^3-3xyz
=[( x+y)^3-3x^2y-3xy^2]+z^3-3xyz
=[(x+y)^3+z^3]-(3x^2y+3xy^2+3xyz)
=(x+y+z)[(x+y)^2-(x+y)z+z^2]-3xy(x+y+z)
=(x+y+z)(x^2+y^2+2xy-xz-yz+z^2)-3xy(x+y+z)
=(x+y+z)(x^2+y^2+z^2-xy-xz-yz)
("是平方"'是三次方)原式=(x"'+y"'+z"'-xyz-xyz-xyz)+xy"-xy"+xz"-xz"+x"y-x"y+x"z-x"z+zy"-zy"+yz"-yz"=(x"'+xy"+xz"-x"y-xyz-x"z)+(x"y+y"'+yz"-xy"-zy"-xyz)+(x"z+zy"+z"'-xyz-yz"-xz")=x(x"+y"+z"-xy-yz-xz)+y(x"+y"+z"-xy-yz-xz)+z(x"+y"+z"-xy-yz-xz)=(x+y+z)(x"+y"+z"-xy-yz-xz)
x+y+z-3xyz怎么因式分解?
2x+3y+4z,xyz
24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y)
3x^2y-{xyz-（2xyz-x^2z）-4x^2z+[3x^2y-(4xyz-5x^z-3xyz)]}化简
x^3+x^2y-x^z-xyz分解因式
x^3+y^3+z^3-3xyz变成(x+y+z)(x^2+y^2+z^2-xy-yz-xz)步骤
已知x+y+z=0求证x*x*x+y*y*y+z*z*z=3xyz
先化简,再求值：3xyz+2(x²y+y²z-xyz)-xyz+2z²x,其中x=1、y=-1、z=2;
先化简再求值3xyz+2(x^2y+y^2z-xyz)-xyz+2z^2x x=1 y= -1 z=2
24xy²z²(x+y-z)-32xyz(z-x-y)²+8xyz³(z-x-y) 为 -8xyz(z-x-y)(3yz+4z-4x-4y+z²)我的过程是这样的：解：原式=-24xy²z²(z-x-y)-32xyz(z-x-y)²+8xyz²(z-x-y)=-[24xy²z²(z-x-y)+32xyz(z-x-y)²+8
x^3+y^3+z^3-3xyz因式分解
x^3-8y^3-z^3-6xyz
3x²y-[2x²y-(2xyz-x²z)-4x²z]-xyz,其中x=-2 y=-3 z=1
3x^2y-[2x^2y-(2xyz-x^2z)-4x^2z]-xyz ,其中x=-2,y=-3,z=1
X^2Y-[-X^2Y+(XYZ-X^2Z)+XYZ]-X^2Z,其中x=-1,y=-2,z=1/3
已知:xyz+xy+xz+yz+x+y+z=3 求：u=xyz(x+y+z) 的最大值
24xy^2*z^2(x+y-z)-32xyz(z-x-y)^2+8xyz^3(z-x-y）