作业帮求值Cos pai/17 *cos 2pai/17*cos 4pai/17*cos 8pai/17
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/04 06:32:31
求值Cos pai/17 *cos 2pai/17*cos 4pai/17*cos 8pai/17
求值Cos pai/17 *cos 2pai/17*cos 4pai/17*cos 8pai/17
求值Cos pai/17 *cos 2pai/17*cos 4pai/17*cos 8pai/17
cos(π/17)cos(2π/17)cos(4π/17)cos(8π/17)
=[16sin(π/17)cos(π/17)cos(2π/17)cos(4π/17)cos(8π/17)]/16sin(π/17)
=[8sin(2π/17)cos(2π/17)cos(4π/17)cos(8π/17)]/16sin(π/17)
=[4sin(4π/17)cos(4π/17)cos(8π/17)]/16sin(π/17)
=[2sin(8π/17)cos(8π/17)]/16sin(π/17)
=sin(16π/17)/16sin(π/17)
=1/16
cosπ/17cos2π/17cos4π/17cos8π/17
=sinπ/17*cosπ/17*cos2π/17*cos4π/17*cos8π/17 / sinπ/17
=1/2*sin2π/17*cos2π/17*cos4π/17*cos8π/17 / sinπ/17
=1/4sin4π/17*cos4π/17*cos8π/17 / sinπ/17
=1/8*sin8π/17*cos8π/17 / sinπ/17
=1/16*sin16π/17 / sinπ/17
sin16π/17=sinπ/17
所以原式=1/16
求值Cos pai/17 *cos 2pai/17*cos 4pai/17*cos 8pai/17
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
求值:cos(2pai/7)+cos(4pai/7)+cos(6pai/7)pai打不出,不好意思
高中三角函数化简求值问题Cos(pai/17)*cos(2pai/17)*cos(4pai/17)*cos(8pai/17)=?详细过程或解法
求值cos(2arctan根号6+pai/3)
cos(-pai-a) 化简求值
sin^4pai/8+cos^4pai/8求值
sin^2(a+pai)-cos(pai+a)*cos(-a)+1
COS(PAI/5)COS(2PAI/5)=?XIE
sin(a-3pai)cos(pai-a) / cos(pai/2 - a)cos(pai+a)sin(pai/2 + a)
cos^2A+cos^2(pai/3+A)+cos^2(pai/3-A)pai姐系派化简
化简cos(pai/7)*cos(2pai/7)*cos(4pai/7)
化简:[sin(a+2pai)cos(pai+a)]/[sin(-pai-a)cos(-pai-a)]
化简：sin(2pai-a)cos(pai a)/cos(pai-a)sin(3pai-a)
三角函数之求值问题sin(pai/6-α)=1/3则cos(2pai/3+2α)= (pai为圆周率）
sin(pai-a)cos(2pai-a)tan(-a+pai)/-tan(-a-pai)sin(-pai-a)
[tan(pai-a)cos(2pai-a)sin(-a+3pai/2)]/[cos(-a-pai)sin(-pai-a)]=