求极限...帮我看看我解答的对不对就行了lim(x趋向0)sin(2x+5x^2)/(ln(e^x+x-x^2))=[sin(2x+5x^2)/(2x+5x^2)][(2x+5x^2)/(ln(e^x+x-x^2)]=(2x+5x^2)/ln(1+1/[1/(x-x^2)])^[1/(x-x^2)](x-x^2)=(2x+5x^2)/(x-x^2)=(2+5x)/(1-x)=-5

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 03:35:17
求极限...帮我看看我解答的对不对就行了lim(x趋向0)sin(2x+5x^2)/(ln(e^x+x-x^2))=[sin(2x+5x^2)/(2x+5x^2)][(2x+5x^2)/(ln(e^x+x-x^2)]=(2x+5x^2)/ln(1+1/[1/(x-x^2)])^[1/(x-x^2)](x-x^2)=(2x+5x^2)/(x-x^2)=(2+5x)/(1-x)=-5

求极限...帮我看看我解答的对不对就行了lim(x趋向0)sin(2x+5x^2)/(ln(e^x+x-x^2))=[sin(2x+5x^2)/(2x+5x^2)][(2x+5x^2)/(ln(e^x+x-x^2)]=(2x+5x^2)/ln(1+1/[1/(x-x^2)])^[1/(x-x^2)](x-x^2)=(2x+5x^2)/(x-x^2)=(2+5x)/(1-x)=-5
求极限...帮我看看我解答的对不对就行了
lim(x趋向0)sin(2x+5x^2)/(ln(e^x+x-x^2))
=[sin(2x+5x^2)/(2x+5x^2)][(2x+5x^2)/(ln(e^x+x-x^2)]
=(2x+5x^2)/ln(1+1/[1/(x-x^2)])^[1/(x-x^2)](x-x^2)
=(2x+5x^2)/(x-x^2)
=(2+5x)/(1-x)=-5

求极限...帮我看看我解答的对不对就行了lim(x趋向0)sin(2x+5x^2)/(ln(e^x+x-x^2))=[sin(2x+5x^2)/(2x+5x^2)][(2x+5x^2)/(ln(e^x+x-x^2)]=(2x+5x^2)/ln(1+1/[1/(x-x^2)])^[1/(x-x^2)](x-x^2)=(2x+5x^2)/(x-x^2)=(2+5x)/(1-x)=-5
=[sin(2x+5x^2)/(2x+5x^2)][(2x+5x^2)/(ln(e^x+x-x^2)]
=(2x+5x^2)/ln(1+1/[1/(x-x^2)])^[1/(x-x^2)](x-x^2)
=(2x+5x^2)/(x-x^2)
这两个都没有看出为什么来
对(2x+5x^2)/(ln(e^x+x-x^2)利用罗比达法则得到
(2+10x) / [e^x + 1 -2x)/(e^x+x-x^2)]
=2/2=1,和你答案不同.因此我怀疑我看不懂的地方,你实际是弄错了