主要是英文!1.A sum of money is planned to be evenly shared among 10 persons.Due to the absence of 2 persons,each person present can get $30 more.Find the sum of money.已知——The sum of money is X.The amount of money each person get among 10

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主要是英文!1.A sum of money is planned to be evenly shared among 10 persons.Due to the absence of 2 persons,each person present can get $30 more.Find the sum of money.已知——The sum of money is X.The amount of money each person get among 10

主要是英文!1.A sum of money is planned to be evenly shared among 10 persons.Due to the absence of 2 persons,each person present can get $30 more.Find the sum of money.已知——The sum of money is X.The amount of money each person get among 10
主要是英文!
1.A sum of money is planned to be evenly shared among 10 persons.Due to the absence of 2 persons,each person present can get $30 more.Find the sum of money.
已知——The sum of money is X.
The amount of money each person get among 10 persons is __________
The amount of money each person get among 8 person is__________
求方程,填空,
2.72 marbles are divided into two groups.7 times the number of marbles in the smaller group is equal to 5 times that in the larger group.Find the number of marbles in the smaller group.
已知——The marbles number in the smaller group is X.
The number marbles in the larger group is _________
要求和第一题一样.

主要是英文!1.A sum of money is planned to be evenly shared among 10 persons.Due to the absence of 2 persons,each person present can get $30 more.Find the sum of money.已知——The sum of money is X.The amount of money each person get among 10
第一题:有一笔钱平均分给10个人,由于2人缺席,出席的每个人多得了30美元,求总钱数.
已知,总钱数为X,平均分给10个人可以每人可以得到X/10,平均分给8个人每人可以得到X/8
根据题意,列方程X/8-X/10=30,解得X=1200,所以总钱数为1200美元
第二题:72颗弹子被分成两份,少的那一份弹子数的7倍等于多的那一份弹子数的5倍,求少的那一份弹子数是多少.
已知,少的那一份弹子数为X,则多的那一份弹子数为7X/5
根据题意,列方程X+7X/5=72,解得X=30,所以少的那份弹子数为30

1.一笔钱本来有10个人分,现在有两人没来,结果剩下的八个人每人多拿30美元。求这笔钱的总额?------三八240,所以10个人的话每人能分得120美元。八个人就是150美元
2.72个弹珠分成大小两组。小组的7倍是大组的5倍,数量上持平-----所以从数量上讲,小组比大组就等于5比7,一共是12个单元。72除以12等于6.所以每组包含6个弹珠。所以大组等于7乘以6等于42.小组等于5乘...

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1.一笔钱本来有10个人分,现在有两人没来,结果剩下的八个人每人多拿30美元。求这笔钱的总额?------三八240,所以10个人的话每人能分得120美元。八个人就是150美元
2.72个弹珠分成大小两组。小组的7倍是大组的5倍,数量上持平-----所以从数量上讲,小组比大组就等于5比7,一共是12个单元。72除以12等于6.所以每组包含6个弹珠。所以大组等于7乘以6等于42.小组等于5乘以6等于30个。

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第一题,。一定数量的钱计划分给10人,缺席两人,因此分给8个人,每人多得了30,
设X为总钱数,Y为10人时每人应得钱,X=10Y,8(Y+30)=X,,Y=120,X=1200,

1.x/10
x/8
方程:x/10+30=x/8
题目解释:有一笔钱计划分给10个人。因为有2人缺席,每人可以多拿到30美元,找出钱的总数
已知:总钱数:x
10个人每人有?钱
8个人有?钱
2.72个溜溜被分成两份。少的那份的溜溜数目的7倍与多的那份的5倍的数目相等。求少的那份的溜溜数。
设少的...

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1.x/10
x/8
方程:x/10+30=x/8
题目解释:有一笔钱计划分给10个人。因为有2人缺席,每人可以多拿到30美元,找出钱的总数
已知:总钱数:x
10个人每人有?钱
8个人有?钱
2.72个溜溜被分成两份。少的那份的溜溜数目的7倍与多的那份的5倍的数目相等。求少的那份的溜溜数。
设少的那份的MARBLE个数为X个,多的那份为(72-X)个
7X=5(72-X)
X=30
答:少的那份共有30个MARBLES
ANSWER:there are 30 marbles in the smaller group.

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