∫(T-sinT)(1-cosT)2 dT 怎么做?需要详细步骤谢谢...

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∫(T-sinT)(1-cosT)2 dT 怎么做?需要详细步骤谢谢...

∫(T-sinT)(1-cosT)2 dT 怎么做?需要详细步骤谢谢...
∫(T-sinT)(1-cosT)2 dT 怎么做?
需要详细步骤
谢谢...

∫(T-sinT)(1-cosT)2 dT 怎么做?需要详细步骤谢谢...
∫(T-sinT)(1-cosT)^2dT
=∫T[1-2cost+cos^2(T) ]dT-∫sinT(1-cosT)^ dT
=∫T[1-2cost+(1+cos2T)/2]dT-∫(1-cosT)^2 d(1-cosT)
=3T/2-2∫TdsinT+1/4∫Tdsin2T-(1-cosT)^3/3
=3T/2-(1-cosT)^3/3-2TsinT+2∫sinTdT+Tsin2T/4-1/4∫sin2TdT
=3T/2-(1-cosT)^3/3-2TsinT-2cosT+Tsin2T/4+1/8cos2T+C

为什么∫(2sint+cost)+2(2cost-sint)/2sint+cost dt = (t+2ln|2sint+cost|)+C? 求x=e^t*cost,y=e^t*sint所确定的函数的二阶导数,求讲解x't=(e^t)(sint+cost)y't=(e^t)(cost-sint)x''t=(e^t)(sint+cost+cost-sint)=2(e^t)costy''t=(e^t)(cost-sint-sint+cost)=-(e^t)sintdy/dx=(cost-sint)/(sint+cost)d^2 y/d(x^2)=d(dy/dx)/dx=(y''x a∫1/sint*dt-a∫sint*dt =a*ln|tan(t/2)|+a*cost+C a∫1/sint*dt-a∫sint*dt =a*ln|tan(t/2)|+a*cost+C 不懂 1.a∫1/sint*dt-a∫sint*dt =a*ln|tan(t/2)|+a*cost+C 不懂 为什么sint/(1-cost)=cot(t/2) ∫dt/(1+sint+cost) 请问各位数学天才关于∫(arcsinx)²dx=?的这两种做法都正确吗令t=arcsinx,则x=sint,dx=cost dt∫(arcsinx)²dx=∫ t²·cost dt=t²·sint-∫ 2t·sint dt=t²·sint+∫ 2t·d(cost)=t²·sint+2tcost-∫ 2cost dt ∫(T-sinT)(1-cosT)2 dT 怎么做?需要详细步骤谢谢... 设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tcost/4t^2 哪个对?设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2sint-tcost/4t^3 和 sint-tcost/4t^2 哪个对? ∫sint/(cost+sint)dt x=(e^t)sint y=(e^t)cost 求d^2y/dx^2 t趋于0时为什么lim(sint+cost-1)/t=lim(cost-sint)=1) 设X=a(t-sint) Y=a(1-cost) ,求d^2y/dx^2答案是-1/a(1-cost)^2 a∫1/sint*dt-a∫sint*dt =a*ln|tan(t/2)|+a*cost+C他是怎样化出来的 ∫cost/(sint+cost)dt 一道积分题求助(t-sint)√(1-cost) dt(t-sint)√(1-cost) dt 怎么积分,从0-2π...或者求解不定积分. 证明:f(x)=x*cos(x)不是周期函数证明:假设y=xcosx是周期函数,因为周期函数有f(x+T)=f(x)xcosx=(x+T)cos(x+T)=xcosx*cosT-xsinx*sinT+Tcosx*cosT-Tsinx*sinT所以cosT=1 T=kπ/2-xsinx*sinT+Tcosx*cosT-Tsinx*sinT=0-xsinx*sinT-Tsinx*si