1x2+2x3+3x4+.+999x1000

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1x2+2x3+3x4+.+999x1000

1x2+2x3+3x4+.+999x1000
1x2+2x3+3x4+.+999x1000

1x2+2x3+3x4+.+999x1000
每一项这样拆:n*(n+1)=1/3[n*(n+1)(n+2)-(n-1)n(n+1)]
1x2+2x3+3x4+.+999x1000
=[(1x2x3-0x1x2)+(2x3x4-1x2x3)+(3x4x5-2x3x4)+.+(999x1000x1001-998x999x1000)]/3
=[999x1000x1001]/3
=333333000

1x2+2x3+3x4+。。。+999x1000
=1/3×999×1000×1001
=333333000

通项公式
n(n+1)(2n+1)/6+n(n+1)/2
=999*(999+1)*(2*999+1)/6+999*(999+1)/2
=333333000