已知2m-n=3,4m+3n=1,求5n(2m-n)^2-2(n-2m)^3的值式子

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 07:38:43
已知2m-n=3,4m+3n=1,求5n(2m-n)^2-2(n-2m)^3的值式子

已知2m-n=3,4m+3n=1,求5n(2m-n)^2-2(n-2m)^3的值式子
已知2m-n=3,4m+3n=1,求5n(2m-n)^2-2(n-2m)^3的值
式子

已知2m-n=3,4m+3n=1,求5n(2m-n)^2-2(n-2m)^3的值式子
x^2m=3 => x^m = 3^(1/2)
y^3n=2 => y^n=2^(1/3)
(x^3m)^2+(y^n)^3-x^my^4nx^3my^5n
=x^6m + y^3n - x^my^4nx^3my^5n
= (x^m)^6 + (y^n)^3 - (x^m)(y^n)^4 * (x^m)^3 * (y^n)^5
= [3^(1/2)]^6 + [2^(1/3)]^3 - 3^(1/2)* [2^(1/3)]^4 * [3^(1/2)]^3 * [2^(1/3)]^5
=3^3 + 3 - 3^(1/2)* [2^(4/3)] * [3^(3/2)] * [2^(5/3)]
= 9 + 3 - 3^2 * 2^3
= 9+ 3-6*6
= -24

2m-n=3 (1)
4m+3n=1 (2)
(1)*2-(2)可解得n=-1
则所求=5*(-1)*(3)^2-2*(-3)^3=9

=5n(2m-n)²+2(2m-n)³ =(2m-n)²(5n+4m-2n) =(2m-n)²(4m+3n) =3²*1 =9